Catch multiple exceptions

1. Select File->Open Project (Ctrl+Shift+N). The Open Project dialog box appears.
2. Brows down to <UNZIP_DIR>/javaintro2 directory.
3. Select MutipleCatchException project. The MultipleCatchException project appears.
4. Open MultipleCatch.java under MultipleCatchException->Source Pacakges->multiplecatch. (Code-1.20 below) Read the code to see what exceptions will be generated depending on the value that is entered in the JOptionPane dialog box.

package multiplecatch;

import javax.swing.JOptionPane;

public class MultipleCatch {

    /** Creates a new instance of MultipleCatch */
    public MultipleCatch() {
    }

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        // Enter the following values and see what exception is caught.
        //    0, 4, character, <no value>
        try {
            String value = JOptionPane.showInputDialog(null, "Enter value:");

            // Non-numerica value will result an NumberFormatException
            int divisor = Integer.parseInt(value);

            // If the divisor is 0, it will result in ArithmetricException
            System.out.println(3/divisor);
        } catch (NumberFormatException nfe){
            System.out.println("Exception caught by this program: Enter numeric value.");
        } catch (ArithmeticException exc) {
            System.out.println("Exception caught by this program: Divisor was 0.");
        }
        System.out.println("After exception.");
    }

}

Code-1.20: MultipleCatch.java

5. Right click MutipleCatchException project and select Run project. A dialog box appears.
6. Enter the following values in turn and see which exceptions are captured.

0 - should generate ArithmeticException
4 - should work fine
<some characters> - should generate NumberFormatException
<no value> - should generate NumberFormatException